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49^x+1=7^x/3
We move all terms to the left:
49^x+1-(7^x/3)=0
We get rid of parentheses
49^x-7^x/3+1=0
We multiply all the terms by the denominator
49^x*3-7^x+1*3=0
We add all the numbers together, and all the variables
49^x*3-7^x+3=0
Wy multiply elements
147x-7^x+3=0
We move all terms containing x to the left, all other terms to the right
147x-7^x=-3
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